3x^2+9.1x=0

Solution for 3x^2+9.1x=0 equation:

3x^2+9.1x=0

a = 3; b = 9.1; c = 0;
Δ = b2-4ac
Δ = 9.12-4·3·0
Δ = 82.81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.1)-\sqrt{82.81}}{2*3}=\frac{-9.1-\sqrt{82.81}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.1)+\sqrt{82.81}}{2*3}=\frac{-9.1+\sqrt{82.81}}{6}
$